1899 Swiss federal election

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The 52 electoral districts

Federal elections were held in Switzerland on 26 October 1899. The Free Democratic Party retained its majority in the National Council.[1]

Electoral system

The 147 members of the National Council were elected in 52 single- and multi-member constituencies using a three-round system. Candidates had to receive a majority in the first or second round to be elected; if it went to a third round, only a plurality was required. Voters could cast as many votes as there were seats in their constituency.[2] There was one seat for every 20,000 citizens, with seats allocated to cantons in proportion to their population.[2]

Results

Voter turnout was highest in Schaffhausen (where voting was compulsory) at 86.4% and lowest in Obwalden at 21.3%.

Party Votes % Seats +/–
Free Democratic Party 183,216 49.7 84 –2
Catholic People's Party 76,845 20.8 32 +2
Liberal Centre 51,764 14.1 20 –1
Social Democratic Party 35,488 9.6 4 +2
Democratic Group 18,003 4.9 7 –1
Others 3,409 0.9 0 0
Invalid/blank votes 33,015
Total 401,750 100 147 0
Registered voters/turnout 737,696 54.5
Source: Mackie & Rose,[3] BFS (seats)

References

  1. ^ Elections to the National Council 1848–1917: Distribution of seats by party or political orientation Archived 2015-09-23 at the Wayback Machine BFS
  2. ^ a b Dieter Nohlen & Philip Stöver (2010) Elections in Europe: A data handbook, p1886 ISBN 9783832956097
  3. ^ Thomas T Mackie & Richard Rose (1991) The International Almanac of Electoral History, Macmillan

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