1944 Iowa gubernatorial election

1944 Iowa gubernatorial election
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← 1942 November 7, 1944 1946 →
  Robert Blue - Official Portrait - 49th GA.jpg No image.svg
Nominee Robert D. Blue Richard F. Mitchell
Party Republican Democratic
Popular vote 561,827 437,684
Percentage 56.01% 43.63%

1944 Iowa gubernatorial election results map by county.svg
County results

Blue:      50-60%      60-70%      70-80%

Mitchell:      50-60%

Governor before election

Bourke B. Hickenlooper
Republican

Elected Governor

Robert D. Blue
Republican

The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.

Primary elections

Primary elections were held on June 5, 1944.

Democratic primary

Candidates

Results

Democratic primary results
Party Candidate Votes %
Democratic Richard F. Mitchell 38,086 100.00
Total votes 38,086 100.00

Republican primary

Candidates

Results

Republican primary results
Party Candidate Votes %
Republican Robert D. Blue 102,246
Republican Henry W. Burma 63,011
Republican Milton W. Strickler 9,859
Total votes

General election

Candidates

Major party candidates

  • Robert D. Blue, Republican
  • Richard F. Mitchell, Democratic

Other candidates

  • Glen Williamson, Prohibition
  • Hugo Bockewitz, Socialist

Results

1944 Iowa gubernatorial election
Party Candidate Votes % ±%
Republican Robert D. Blue 561,827 56.01%
Democratic Richard F. Mitchell 437,684 43.63%
Prohibition Glen Williamson 2,815 0.28%
Socialist Hugo Bockewitz 832 0.08%
Majority 124,143
Turnout
Republican hold Swing

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